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SCIENCE CHINA Technological Sciences, Volume 59 , Issue 10 : 1507-1516(2016) https://doi.org/10.1007/s11431-016-0132-x

Entransy dissipation minimization for generalized heat exchange processes

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  • ReceivedFeb 20, 2016
  • AcceptedJul 18, 2016
  • PublishedSep 14, 2016

Abstract

This paper investigates the MED (Minimum Entransy Dissipation) optimization of heat transfer processes with the generalized heat transfer law q (Δ(T n) )m . For the fixed amount of heat transfer, the optimal temperature paths for the MED are obtained. The results show that the strategy of the MED with generalized convective law q (ΔT)m is that the temperature difference keeps constant, which is in accordance with the famous temperature-difference-field uniformity principle, while the strategy of the MED with linear phenomenological law q Δ(T 1) is that the temperature ratio keeps constant. For special cases with Dulong-Petit law q (ΔT)1.25 and an imaginary complex law q (Δ( T4 )) 1.25 , numerical examples are provided and further compared with the strategies of the MEG (Minimum Entropy Generation), CHF (Constant Heat Flux) and CRT (Constant Reservoir Temperature) operations. Besides, influences of the change of the heat transfer amount on the optimization results with various heat resistance models are discussed in detail.


Acknowledgment

This work was supported by the National Natural Science Foundation of China (Grant Nos. 51576207, 51356001 & 51579244).


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  • Figure 1

    Three types of simple two-fluid heat exchangers.

  • Figure 2

    Model of zero-dimensional transient heat exchange process.

  • Figure 3

    The time variations of reservoir temperature T1 for the four heat exchange strategies under [q (ΔT)1.25 ]. (a) ΔT2=100 K; (b) ΔT2=600 K.

  • Figure 4

    The time variations of reservoir temperature T1 for the four heat exchange strategies under [q(Δ(T4))1.25]. (a) ΔT2=100 K; (b) ΔT2=600 K.

  • Figure 5

    The optimal reservoir temperature paths for the strategies of ΔE=min under different thermal resistance models. (a) ΔT2=100 K; (b) ΔT2=600 K.

  • Table 1   Comparison of the results for various strategies under []

    Case

    ΔT2=100 K

    ΔT2=600 K

    T1(0) (K)

    T1(τ) (K)

    ΔS/ΔSmin

    ΔE/ΔEmin

    T1(0) (K)

    T1(τ) (K)

    ΔS/ΔSmin

    ΔE/ΔEmin

    T1=const

    420.8

    420.8

    1.241

    1.288

    956.8

    956.8

    1.412

    1.549

    q=const

    355.1

    455.0

    1.004

    1.000

    530.9

    1130.9

    1.029

    1.000

    ΔS=min

    348.4

    462.3

    1.000

    1.006

    439.4

    1253.9

    1.000

    1.081

    ΔE=min

    355.1

    455.0

    1.004

    1.000

    530.9

    1130.9

    1.029

    1.000

  • Table 2   Comparison of the results for various strategies under [(())]

    Case

    ΔT2=100 K

    ΔT2=600 K

    T1(0) (K)

    T1(τ) (K)

    ΔS/ΔSmin

    ΔE/ΔEmin

    T1(0) (K)

    T1(τ) (K)

    ΔS/ΔSmin

    ΔE/ΔEmin

    T1=const

    451.3

    451.3

    1.028

    1.031

    947.2

    947.2

    1.052

    1.087

    q=const

    426.9

    474.4

    1.002

    1.001

    818.9

    1022.8

    1.011

    1.003

    ΔS=min

    413.6

    486.2

    1.000

    1.004

    763.0

    1083.2

    1.000

    1.012

    ΔE=min

    420.3

    480.3

    1.002

    1.000

    792.3

    1050.6

    1.003

    1.000

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